59-(26+3)=4(c+7)=c

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Solution for 59-(26+3)=4(c+7)=c equation:



59-(26+3)=4(c+7)=c
We move all terms to the left:
59-(26+3)-(4(c+7))=0
We add all the numbers together, and all the variables
-(4(c+7))+59-29=0
We add all the numbers together, and all the variables
-(4(c+7))+30=0
We calculate terms in parentheses: -(4(c+7)), so:
4(c+7)
We multiply parentheses
4c+28
Back to the equation:
-(4c+28)
We get rid of parentheses
-4c-28+30=0
We add all the numbers together, and all the variables
-4c+2=0
We move all terms containing c to the left, all other terms to the right
-4c=-2
c=-2/-4
c=1/2

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