59-(26+3)=4(c+7)=c

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Solution for 59-(26+3)=4(c+7)=c equation: 



59-(26+3)=4(c+7)=c

We move all terms to the left:

59-(26+3)-(4(c+7))=0

We add all the numbers together, and all the variables

-(4(c+7))+59-29=0

We add all the numbers together, and all the variables

-(4(c+7))+30=0



We calculate terms in parentheses: -(4(c+7)), so:

4(c+7)

We multiply parentheses

4c+28

Back to the equation:

-(4c+28)



We get rid of parentheses

-4c-28+30=0

We add all the numbers together, and all the variables

-4c+2=0

We move all terms containing c to the left, all other terms to the right

-4c=-2

c=-2/-4

c=1/2

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