59-(2c+3)=4(c-7)+c

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Solution for 59-(2c+3)=4(c-7)+c equation: 



59-(2c+3)=4(c-7)+c

We move all terms to the left:

59-(2c+3)-(4(c-7)+c)=0

We get rid of parentheses

-2c-(4(c-7)+c)-3+59=0



We calculate terms in parentheses: -(4(c-7)+c), so:

4(c-7)+c

We add all the numbers together, and all the variables

c+4(c-7)

We multiply parentheses

c+4c-28

We add all the numbers together, and all the variables

5c-28

Back to the equation:

-(5c-28)



We add all the numbers together, and all the variables

-2c-(5c-28)+56=0

We get rid of parentheses

-2c-5c+28+56=0

We add all the numbers together, and all the variables

-7c+84=0

We move all terms containing c to the left, all other terms to the right

-7c=-84

c=-84/-7

c=+12

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