590-6(x+1)=22-10(1-x)

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Solution for 590-6(x+1)=22-10(1-x) equation: 



590-6(x+1)=22-10(1-x)

We move all terms to the left:

590-6(x+1)-(22-10(1-x))=0

We add all the numbers together, and all the variables

-6(x+1)-(22-10(-1x+1))+590=0

We multiply parentheses

-6x-(22-10(-1x+1))-6+590=0



We calculate terms in parentheses: -(22-10(-1x+1)), so:

22-10(-1x+1)

determiningTheFunctionDomain
-10(-1x+1)+22

We multiply parentheses

10x-10+22

We add all the numbers together, and all the variables

10x+12

Back to the equation:

-(10x+12)



We add all the numbers together, and all the variables

-6x-(10x+12)+584=0

We get rid of parentheses

-6x-10x-12+584=0

We add all the numbers together, and all the variables

-16x+572=0

We move all terms containing x to the left, all other terms to the right

-16x=-572

x=-572/-16

x=35+3/4

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