594=(20-2x)(30+3x)

Solution for 594=(20-2x)(30+3x) equation:

594=(20-2x)(30+3x)

We move all terms to the left:

594-((20-2x)(30+3x))=0

We add all the numbers together, and all the variables

-((-2x+20)(3x+30))+594=0

We multiply parentheses ..

-((-6x^2-60x+60x+600))+594=0


We calculate terms in parentheses: -((-6x^2-60x+60x+600)), so:

(-6x^2-60x+60x+600)

We get rid of parentheses

-6x^2-60x+60x+600

We add all the numbers together, and all the variables

-6x^2+600

Back to the equation:

-(-6x^2+600)


We get rid of parentheses

6x^2-600+594=0

We add all the numbers together, and all the variables

6x^2-6=0

a = 6; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·6·(-6)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*6}=\frac{-12}{12}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*6}=\frac{12}{12}
=1
$