5=(-40)/a

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Solution for 5=(-40)/a equation:



5=(-40)/a
We move all terms to the left:
5-((-40)/a)=0
Domain of the equation: a)!=0
a!=0/1
a!=0
a∈R
We multiply all the terms by the denominator
-((-40)+5*a)=0
We calculate terms in parentheses: -((-40)+5*a), so:
(-40)+5*a
determiningTheFunctionDomain 5*a+(-40)
We add all the numbers together, and all the variables
5a-40
Back to the equation:
-(5a-40)
We get rid of parentheses
-5a+40=0
We move all terms containing a to the left, all other terms to the right
-5a=-40
a=-40/-5
a=+8

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