5=(-8+3x)/(2)

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Solution for 5=(-8+3x)/(2) equation: 



5=(-8+3x)/(2)

We move all terms to the left:

5-((-8+3x)/(2))=0

We add all the numbers together, and all the variables

-((3x-8)/2)+5=0

We multiply all the terms by the denominator


-((3x-8)+5*2)=0



We calculate terms in parentheses: -((3x-8)+5*2), so:

(3x-8)+5*2

We add all the numbers together, and all the variables

(3x-8)+10

We get rid of parentheses

3x-8+10

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We get rid of parentheses

-3x-2=0

We move all terms containing x to the left, all other terms to the right

-3x=2

x=2/-3

x=-2/3

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