5=(1-3x)2+x/2

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Solution for 5=(1-3x)2+x/2 equation: 



5=(1-3x)2+x/2

We move all terms to the left:

5-((1-3x)2+x/2)=0

We add all the numbers together, and all the variables

-((-3x+1)2+x/2)+5=0

We multiply all the terms by the denominator


-((-3x+1)2+x+5*2)=0



We calculate terms in parentheses: -((-3x+1)2+x+5*2), so:

(-3x+1)2+x+5*2

We add all the numbers together, and all the variables

x+(-3x+1)2+10

We multiply parentheses

x-6x+2+10

We add all the numbers together, and all the variables

-5x+12

Back to the equation:

-(-5x+12)



We get rid of parentheses

5x-12=0

We move all terms containing x to the left, all other terms to the right

5x=12

x=12/5

x=2+2/5

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