5=(1-c)/11

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Solution for 5=(1-c)/11 equation: 



5=(1-c)/11

We move all terms to the left:

5-((1-c)/11)=0

We add all the numbers together, and all the variables

-((-1c+1)/11)+5=0

We multiply all the terms by the denominator


-((-1c+1)+5*11)=0



We calculate terms in parentheses: -((-1c+1)+5*11), so:

(-1c+1)+5*11

We add all the numbers together, and all the variables

(-1c+1)+55

We get rid of parentheses

-1c+1+55

We add all the numbers together, and all the variables

-1c+56

Back to the equation:

-(-1c+56)



We get rid of parentheses

1c-56=0

We add all the numbers together, and all the variables

c-56=0

We move all terms containing c to the left, all other terms to the right

c=56

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