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5=(1/2)v-3
We move all terms to the left:
5-((1/2)v-3)=0
Domain of the equation: 2)v-3)!=0We add all the numbers together, and all the variables
v!=0/1
v!=0
v∈R
-((+1/2)v-3)+5=0
We multiply all the terms by the denominator
-((+1+5*2)v-3)=0
We calculate terms in parentheses: -((+1+5*2)v-3), so:We get rid of parentheses
(+1+5*2)v-3
We add all the numbers together, and all the variables
11v-3
Back to the equation:
-(11v-3)
-11v+3=0
We move all terms containing v to the left, all other terms to the right
-11v=-3
v=-3/-11
v=3/11
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