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5=(10x+15)/(5x-2)
We move all terms to the left:
5-((10x+15)/(5x-2))=0
Domain of the equation: (5x-2))!=0We multiply all the terms by the denominator
x∈R
-((10x+15)+5*(5x-2))=0
We calculate terms in parentheses: -((10x+15)+5*(5x-2)), so:We get rid of parentheses
(10x+15)+5*(5x-2)
We multiply parentheses
(10x+15)+25x-10
We get rid of parentheses
10x+25x+15-10
We add all the numbers together, and all the variables
35x+5
Back to the equation:
-(35x+5)
-35x-5=0
We move all terms containing x to the left, all other terms to the right
-35x=5
x=5/-35
x=-1/7
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