5=(1x+2)

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Solution for 5=(1x+2) equation: 



5=(1x+2)

We move all terms to the left:

5-((1x+2))=0

We add all the numbers together, and all the variables

-((x+2))+5=0



We calculate terms in parentheses: -((x+2)), so:

(x+2)

We get rid of parentheses

x+2

Back to the equation:

-(x+2)



We get rid of parentheses

-x-2+5=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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