5=(2a+4)-3(4a+2)

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Solution for 5=(2a+4)-3(4a+2) equation: 



5=(2a+4)-3(4a+2)

We move all terms to the left:

5-((2a+4)-3(4a+2))=0



We calculate terms in parentheses: -((2a+4)-3(4a+2)), so:

(2a+4)-3(4a+2)

We multiply parentheses

(2a+4)-12a-6

We get rid of parentheses

2a-12a+4-6

We add all the numbers together, and all the variables

-10a-2

Back to the equation:

-(-10a-2)



We get rid of parentheses

10a+2+5=0

We add all the numbers together, and all the variables

10a+7=0

We move all terms containing a to the left, all other terms to the right

10a=-7

a=-7/10

a=-7/10

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