5=(5/9)(x-32)

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Solution for 5=(5/9)(x-32) equation:



5=(5/9)(x-32)
We move all terms to the left:
5-((5/9)(x-32))=0
Domain of the equation: 9)(x-32))!=0
x∈R
We add all the numbers together, and all the variables
-((+5/9)(x-32))+5=0
We multiply parentheses ..
-((+5x^2+5/9*-32))+5=0
We multiply all the terms by the denominator
-((+5x^2+5+5*9*-32))=0
We calculate terms in parentheses: -((+5x^2+5+5*9*-32)), so:
(+5x^2+5+5*9*-32)
We get rid of parentheses
5x^2+5-32+5*9*
We add all the numbers together, and all the variables
5x^2
Back to the equation:
-(5x^2)
a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-10}=0$

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