5=(x+2)+3(2x-18)

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Solution for 5=(x+2)+3(2x-18) equation: 



5=(x+2)+3(2x-18)

We move all terms to the left:

5-((x+2)+3(2x-18))=0



We calculate terms in parentheses: -((x+2)+3(2x-18)), so:

(x+2)+3(2x-18)

We multiply parentheses

(x+2)+6x-54

We get rid of parentheses

x+6x+2-54

We add all the numbers together, and all the variables

7x-52

Back to the equation:

-(7x-52)



We get rid of parentheses

-7x+52+5=0

We add all the numbers together, and all the variables

-7x+57=0

We move all terms containing x to the left, all other terms to the right

-7x=-57

x=-57/-7

x=8+1/7

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