5=(z/4)+2

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Solution for 5=(z/4)+2 equation: 



5=(z/4)+2

We move all terms to the left:

5-((z/4)+2)=0

We add all the numbers together, and all the variables

-((+z/4)+2)+5=0

We multiply all the terms by the denominator


-((+z+5*4)+2)=0



We calculate terms in parentheses: -((+z+5*4)+2), so:

(+z+5*4)+2

We add all the numbers together, and all the variables

(z+20)+2

We get rid of parentheses

z+20+2

We add all the numbers together, and all the variables

z+22

Back to the equation:

-(z+22)



We get rid of parentheses

-z-22=0

We add all the numbers together, and all the variables

-1z-22=0

We move all terms containing z to the left, all other terms to the right

-z=22

z=22/-1

z=-22

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