5=(z/4)-3

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Solution for 5=(z/4)-3 equation: 



5=(z/4)-3

We move all terms to the left:

5-((z/4)-3)=0

We add all the numbers together, and all the variables

-((+z/4)-3)+5=0

We multiply all the terms by the denominator


-((+z+5*4)-3)=0



We calculate terms in parentheses: -((+z+5*4)-3), so:

(+z+5*4)-3

We add all the numbers together, and all the variables

(z+20)-3

We get rid of parentheses

z+20-3

We add all the numbers together, and all the variables

z+17

Back to the equation:

-(z+17)



We get rid of parentheses

-z-17=0

We add all the numbers together, and all the variables

-1z-17=0

We move all terms containing z to the left, all other terms to the right

-z=17

z=17/-1

z=-17

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