5=-(2+c)-(14+2c)

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Solution for 5=-(2+c)-(14+2c) equation: 



5=-(2+c)-(14+2c)

We move all terms to the left:

5-(-(2+c)-(14+2c))=0

We add all the numbers together, and all the variables

-(-(c+2)-(2c+14))+5=0



We calculate terms in parentheses: -(-(c+2)-(2c+14)), so:

-(c+2)-(2c+14)

We get rid of parentheses

-c-2c-2-14

We add all the numbers together, and all the variables

-3c-16

Back to the equation:

-(-3c-16)



We get rid of parentheses

3c+16+5=0

We add all the numbers together, and all the variables

3c+21=0

We move all terms containing c to the left, all other terms to the right

3c=-21

c=-21/3

c=-7

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