5=-(2+c)-(14+2c)

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Solution for 5=-(2+c)-(14+2c) equation:



5=-(2+c)-(14+2c)
We move all terms to the left:
5-(-(2+c)-(14+2c))=0
We add all the numbers together, and all the variables
-(-(c+2)-(2c+14))+5=0
We calculate terms in parentheses: -(-(c+2)-(2c+14)), so:
-(c+2)-(2c+14)
We get rid of parentheses
-c-2c-2-14
We add all the numbers together, and all the variables
-3c-16
Back to the equation:
-(-3c-16)
We get rid of parentheses
3c+16+5=0
We add all the numbers together, and all the variables
3c+21=0
We move all terms containing c to the left, all other terms to the right
3c=-21
c=-21/3
c=-7

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