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x in (-oo:+oo)
5 = x*(((-1/2)*(2*x-4))/2) // - x*(((-1/2)*(2*x-4))/2)
5-(x*(((-1/2)*(2*x-4))/2)) = 0
(1/4)*x*(2*x-4)+5 = 0
1/4*x*(2*x-4)+5 = 0
1/4*x*(2*x-4)+5 = 0
1/2*x^2-x+5 = 0
1/2*x^2-x+5 = 0
1/2*x^2-x+5 = 0
DELTA = (-1)^2-(1/2*4*5)
DELTA = -9
DELTA < 0
1 = 0
1 = 0
x belongs to the empty set
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