5=-2k+3/4(3k+2)

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Solution for 5=-2k+3/4(3k+2) equation: 


k in (-oo:+oo)

5 = (3/4)*(3*k+2)-2*k // - (3/4)*(3*k+2)-2*k

5-((3/4)*(3*k+2))-(-2*k) = 0

(-3/4)*(3*k+2)+2*k+5 = 0

2*k-3/4*(3*k+2)+5 = 0

2*k-3/4*(3*k+2)+5 = 0

5-1/4*k-3/2 = 0

7/2-1/4*k = 0

7/2-1/4*k = 0

7/2-1/4*k = 0 // - 7/2

-1/4*k = -7/2 // : -1/4

k = -7/2/(-1/4)

k = 14

k = 14

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