5=-3/1(-3)+b

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Solution for 5=-3/1(-3)+b equation: 



5=-3/1(-3)+b

We move all terms to the left:

5-(-3/1(-3)+b)=0



Domain of the equation: 1(-3)+b)!=0

b∈R



We multiply all the terms by the denominator


-(-3+5*1(-3)+b)=0



We calculate terms in parentheses: -(-3+5*1(-3)+b), so:

-3+5*1(-3)+b

determiningTheFunctionDomain
b-3+5*1(-3)

We add all the numbers together, and all the variables

b-18

Back to the equation:

-(b-18)



We get rid of parentheses

-b+18=0

We add all the numbers together, and all the variables

-1b+18=0

We move all terms containing b to the left, all other terms to the right

-b=-18

b=-18/-1

b=+18

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