5=-4/3(2)+b

Solution for 5=-4/3(2)+b equation:

5=-4/3(2)+b

We move all terms to the left:

5-(-4/3(2)+b)=0


Domain of the equation: 32+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-32

b!=-32/1

b!=-32

b∈R


We add all the numbers together, and all the variables

-(+b-4/32)+5=0

We get rid of parentheses

-b+5+4/32=0

We multiply all the terms by the denominator


-b*32+4+5*32=0

We add all the numbers together, and all the variables

-b*32+164=0

Wy multiply elements

-32b+164=0

We move all terms containing b to the left, all other terms to the right

-32b=-164

b=-164/-32

b=5+1/8