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5=-9/5(-5)+b
We move all terms to the left:
5-(-9/5(-5)+b)=0
Domain of the equation: 5(-5)+b)!=0We multiply all the terms by the denominator
b∈R
-(-9+5*5(-5)+b)=0
We calculate terms in parentheses: -(-9+5*5(-5)+b), so:We get rid of parentheses
-9+5*5(-5)+b
determiningTheFunctionDomain b-9+5*5(-5)
We add all the numbers together, and all the variables
b-134
Back to the equation:
-(b-134)
-b+134=0
We add all the numbers together, and all the variables
-1b+134=0
We move all terms containing b to the left, all other terms to the right
-b=-134
b=-134/-1
b=+134
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