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5=-9/5-5+b
We move all terms to the left:
5-(-9/5-5+b)=0
Domain of the equation: 5-5+b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-(b-9/5-5)+5=0
We get rid of parentheses
-b+5+5+9/5=0
We multiply all the terms by the denominator
-b*5+9+5*5+5*5=0
We add all the numbers together, and all the variables
-b*5+59=0
Wy multiply elements
-5b+59=0
We move all terms containing b to the left, all other terms to the right
-5b=-59
b=-59/-5
b=11+4/5
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