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5=1/2(3x+2)
We move all terms to the left:
5-(1/2(3x+2))=0
Domain of the equation: 2(3x+2))!=0We multiply all the terms by the denominator
x∈R
-(1+5*2(3x+2))=0
We calculate terms in parentheses: -(1+5*2(3x+2)), so:We add all the numbers together, and all the variables
1+5*2(3x+2)
determiningTheFunctionDomain 5*2(3x+2)+1
Wy multiply elements
10x(3+1
Back to the equation:
-(10x(3+1)
-(10x4=0
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