5=1/2(3x-2)

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Solution for 5=1/2(3x-2) equation:



5=1/2(3x-2)
We move all terms to the left:
5-(1/2(3x-2))=0
Domain of the equation: 2(3x-2))!=0
x∈R
We multiply all the terms by the denominator
-(1+5*2(3x-2))=0
We calculate terms in parentheses: -(1+5*2(3x-2)), so:
1+5*2(3x-2)
determiningTheFunctionDomain 5*2(3x-2)+1
Wy multiply elements
10x(3+1
Back to the equation:
-(10x(3+1)
We add all the numbers together, and all the variables
-(10x4=0

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