5=1/2(3x-2)

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Solution for 5=1/2(3x-2) equation: 



5=1/2(3x-2)

We move all terms to the left:

5-(1/2(3x-2))=0



Domain of the equation: 2(3x-2))!=0

x∈R



We multiply all the terms by the denominator


-(1+5*2(3x-2))=0



We calculate terms in parentheses: -(1+5*2(3x-2)), so:

1+5*2(3x-2)

determiningTheFunctionDomain
5*2(3x-2)+1

Wy multiply elements

10x(3+1

Back to the equation:

-(10x(3+1)



We add all the numbers together, and all the variables

-(10x4=0

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