5=1/2(4c+10)-2c

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Solution for 5=1/2(4c+10)-2c equation: 



5=1/2(4c+10)-2c

We move all terms to the left:

5-(1/2(4c+10)-2c)=0



Domain of the equation: 2(4c+10)-2c)!=0

c∈R



We multiply all the terms by the denominator


-(1+5*2(4c+10)-2c)=0



We calculate terms in parentheses: -(1+5*2(4c+10)-2c), so:

1+5*2(4c+10)-2c

determiningTheFunctionDomain
5*2(4c+10)-2c+1

We add all the numbers together, and all the variables

-2c+5*2(4c+10)+1

Wy multiply elements

-2c+10c(4+1

Back to the equation:

-(-2c+10c(4+1)



We add all the numbers together, and all the variables

-(-2c+10c5=0

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