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5=1/2x-1.5+2x
We move all terms to the left:
5-(1/2x-1.5+2x)=0
Domain of the equation: 2x-1.5+2x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x+2x)!=1.5
x∈R
-(2x+1/2x-1.5)+5=0
We get rid of parentheses
-2x-1/2x+1.5+5=0
We multiply all the terms by the denominator
-2x*2x+(1.5)*2x+5*2x-1=0
We multiply parentheses
-2x*2x+3x+5*2x-1=0
Wy multiply elements
-4x^2+3x+10x-1=0
We add all the numbers together, and all the variables
-4x^2+13x-1=0
a = -4; b = 13; c = -1;
Δ = b2-4ac
Δ = 132-4·(-4)·(-1)
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-3\sqrt{17}}{2*-4}=\frac{-13-3\sqrt{17}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+3\sqrt{17}}{2*-4}=\frac{-13+3\sqrt{17}}{-8} $
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