5=1/3(2x+12)

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Solution for 5=1/3(2x+12) equation: 



5=1/3(2x+12)

We move all terms to the left:

5-(1/3(2x+12))=0



Domain of the equation: 3(2x+12))!=0

x∈R



We multiply all the terms by the denominator


-(1+5*3(2x+12))=0



We calculate terms in parentheses: -(1+5*3(2x+12)), so:

1+5*3(2x+12)

determiningTheFunctionDomain
5*3(2x+12)+1

Wy multiply elements

15x(2+1

Back to the equation:

-(15x(2+1)



We add all the numbers together, and all the variables

-(15x3=0

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