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5=1/3(t-6)
We move all terms to the left:
5-(1/3(t-6))=0
Domain of the equation: 3(t-6))!=0We multiply all the terms by the denominator
t∈R
-(1+5*3(t-6))=0
We calculate terms in parentheses: -(1+5*3(t-6)), so:
1+5*3(t-6)
determiningTheFunctionDomain 5*3(t-6)+1
Wy multiply elements
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Back to the equation:
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| 9b-2b=-14+9b | | 5-2*14}^{3.2x}=4 | | V=x(14-2x)(8.5-2x)(x) | | 3(-7x-8)=24+3x | | -4x-1+6=-7 | | 5×x=30-10 | | 5(x+4)=-6+5(x-2) | | 45n=580 | | Y=5/5u+5;u | | B(x)=25.00-0.08(x) | | 1/7x+1/8=9/56 | | -5.6k=-2.88 | | 8k-6+3k-2k=4*22 | | 2x+40+x+10=180 | | 2x+40+x+10=189 | | 2/x+3+4=5-x/x+3 | | 7x-9=2x-16 | | 1/x+3=1/x+1/3 | | -18+58=-5(x+5) | | 3(4x+8)=-45+9 | | -3n-6n=9 | | 2s+6=102 | | 2w-8-5w=-3w-2w+6 | | 6^2x=81 | | 16(4-3m)=48(-m+2) | | f/60=2 | | (4x/2-2x/4)^2+9x=-9 | | f/60=2 | | 2u^2-11u+18=(u-4)^2 | | –13j+9=–12j+18 | | 5(2d+3)=6(d-1)+1 | | 2-3(x-4)=2(x-1) |