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5=1/5(300-5e)
We move all terms to the left:
5-(1/5(300-5e))=0
Domain of the equation: 5(300-5e))!=0We add all the numbers together, and all the variables
e∈R
-(1/5(-5e+300))+5=0
We multiply all the terms by the denominator
-(1+5*5(-5e+300))=0
We calculate terms in parentheses: -(1+5*5(-5e+300)), so:
1+5*5(-5e+300)
determiningTheFunctionDomain 5*5(-5e+300)+1
Wy multiply elements
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We use the square of the difference formula
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Back to the equation:
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