5=1/5(65-10e)

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Solution for 5=1/5(65-10e) equation:



5=1/5(65-10e)
We move all terms to the left:
5-(1/5(65-10e))=0
Domain of the equation: 5(65-10e))!=0
e∈R
We add all the numbers together, and all the variables
-(1/5(-10e+65))+5=0
We multiply all the terms by the denominator
-(1+5*5(-10e+65))=0
We calculate terms in parentheses: -(1+5*5(-10e+65)), so:
1+5*5(-10e+65)
determiningTheFunctionDomain 5*5(-10e+65)+1
Wy multiply elements
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We use the square of the difference formula
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Back to the equation:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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We calculate terms in parentheses: -(25e(-1), so:
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