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5=1/5(65w-4)
We move all terms to the left:
5-(1/5(65w-4))=0
Domain of the equation: 5(65w-4))!=0We multiply all the terms by the denominator
w∈R
-(1+5*5(65w-4))=0
We calculate terms in parentheses: -(1+5*5(65w-4)), so:We add all the numbers together, and all the variables
1+5*5(65w-4)
determiningTheFunctionDomain 5*5(65w-4)+1
Wy multiply elements
25w(6+1
Back to the equation:
-(25w(6+1)
-(25w7=0
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