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5=1/5h
We move all terms to the left:
5-(1/5h)=0
Domain of the equation: 5h)!=0We add all the numbers together, and all the variables
h!=0/1
h!=0
h∈R
-(+1/5h)+5=0
We get rid of parentheses
-1/5h+5=0
We multiply all the terms by the denominator
5*5h-1=0
Wy multiply elements
25h-1=0
We move all terms containing h to the left, all other terms to the right
25h=1
h=1/25
h=1/25
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