5=1/7(10x+28

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Solution for 5=1/7(10x+28 equation: 



5=1/7(10x+28

We move all terms to the left:

5-(1/7(10x+28)=0



Domain of the equation: 7(10x+28)+5!=0

We move all terms containing x to the left, all other terms to the right

7(10x+28)!=-5

x∈R



We multiply all the terms by the denominator


-(1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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