5=10x+8/x

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Solution for 5=10x+8/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5 = 10*x+8/x // - 10*x+8/x

5-(10*x)-(8/x) = 0

5-10*x-8*x^-1 = 0

5*x^0-10*x^1-8*x^-1 = 0

(5*x^1-10*x^2-8*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^1-10*x^2-8*x^0) = 0

x^1

5*x-10*x^2-8 = 0

5*x-10*x^2-8 = 0

DELTA = 5^2-(-10*(-8)*4)

DELTA = -295

DELTA < 0

x in { } 

x belongs to the empty set

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