5=10z+2(-7z/2-1)

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Solution for 5=10z+2(-7z/2-1) equation: 


z in (-oo:+oo)

5 = 2*((-7*z)/2-1)+10*z // - 2*((-7*z)/2-1)+10*z

5-(2*((-7*z)/2-1))-(10*z) = 0

5-2*((-7*z)/2-1)-10*z = 0

5-2*(-7/2*z-1)-10*z = 0

5-2*(-7/2*z-1)-10*z = 0

2-3*z+5 = 0

7-3*z = 0

7-3*z = 0

7-3*z = 0 // - 7

-3*z = -7 // : -3

z = -7/(-3)

z = 7/3

z = 7/3

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