5=2(6z+4)+10

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Solution for 5=2(6z+4)+10 equation: 



5=2(6z+4)+10

We move all terms to the left:

5-(2(6z+4)+10)=0



We calculate terms in parentheses: -(2(6z+4)+10), so:

2(6z+4)+10

We multiply parentheses

12z+8+10

We add all the numbers together, and all the variables

12z+18

Back to the equation:

-(12z+18)



We get rid of parentheses

-12z-18+5=0

We add all the numbers together, and all the variables

-12z-13=0

We move all terms containing z to the left, all other terms to the right

-12z=13

z=13/-12

z=-1+1/12

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