5=2(u-4)+3

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Solution for 5=2(u-4)+3 equation: 



5=2(u-4)+3

We move all terms to the left:

5-(2(u-4)+3)=0



We calculate terms in parentheses: -(2(u-4)+3), so:

2(u-4)+3

We multiply parentheses

2u-8+3

We add all the numbers together, and all the variables

2u-5

Back to the equation:

-(2u-5)



We get rid of parentheses

-2u+5+5=0

We add all the numbers together, and all the variables

-2u+10=0

We move all terms containing u to the left, all other terms to the right

-2u=-10

u=-10/-2

u=+5

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