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5=2(x-3)+3-x
We move all terms to the left:
5-(2(x-3)+3-x)=0
We calculate terms in parentheses: -(2(x-3)+3-x), so:We get rid of parentheses
2(x-3)+3-x
determiningTheFunctionDomain 2(x-3)-x+3
We add all the numbers together, and all the variables
-1x+2(x-3)+3
We multiply parentheses
-1x+2x-6+3
We add all the numbers together, and all the variables
x-3
Back to the equation:
-(x-3)
-x+3+5=0
We add all the numbers together, and all the variables
-1x+8=0
We move all terms containing x to the left, all other terms to the right
-x=-8
x=-8/-1
x=+8
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