5=2/(z+3)

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Solution for 5=2/(z+3) equation: 



5=2/(z+3)

We move all terms to the left:

5-(2/(z+3))=0



Domain of the equation: (z+3))!=0

z∈R



We multiply all the terms by the denominator


-(2+5*(z+3))=0



We calculate terms in parentheses: -(2+5*(z+3)), so:

2+5*(z+3)

determiningTheFunctionDomain
5*(z+3)+2

We multiply parentheses

5z+15+2

We add all the numbers together, and all the variables

5z+17

Back to the equation:

-(5z+17)



We get rid of parentheses

-5z-17=0

We move all terms containing z to the left, all other terms to the right

-5z=17

z=17/-5

z=-3+2/5

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