5=3(2f+2/3)

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Solution for 5=3(2f+2/3) equation: 



5=3(2f+2/3)

We move all terms to the left:

5-(3(2f+2/3))=0

We add all the numbers together, and all the variables

-(3(+2f+2/3))+5=0

We multiply all the terms by the denominator


-(3(+2f+2+5*3))=0



We calculate terms in parentheses: -(3(+2f+2+5*3)), so:

3(+2f+2+5*3)

We add all the numbers together, and all the variables

3(2f+17)

We multiply parentheses

6f+51

Back to the equation:

-(6f+51)



We get rid of parentheses

-6f-51=0

We move all terms containing f to the left, all other terms to the right

-6f=51

f=51/-6

f=-8+1/2

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