5=3(j-5)-1

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Solution for 5=3(j-5)-1 equation: 



5=3(j-5)-1

We move all terms to the left:

5-(3(j-5)-1)=0



We calculate terms in parentheses: -(3(j-5)-1), so:

3(j-5)-1

We multiply parentheses

3j-15-1

We add all the numbers together, and all the variables

3j-16

Back to the equation:

-(3j-16)



We get rid of parentheses

-3j+16+5=0

We add all the numbers together, and all the variables

-3j+21=0

We move all terms containing j to the left, all other terms to the right

-3j=-21

j=-21/-3

j=+7

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