5=3(y-12)-(-2)

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Solution for 5=3(y-12)-(-2) equation: 



5=3(y-12)-(-2)

We move all terms to the left:

5-(3(y-12)-(-2))=0



We calculate terms in parentheses: -(3(y-12)-(-2)), so:

3(y-12)-(-2)

We add all the numbers together, and all the variables

3(y-12)+2

We multiply parentheses

3y-36+2

We add all the numbers together, and all the variables

3y-34

Back to the equation:

-(3y-34)



We get rid of parentheses

-3y+34+5=0

We add all the numbers together, and all the variables

-3y+39=0

We move all terms containing y to the left, all other terms to the right

-3y=-39

y=-39/-3

y=+13

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