5=4+2(3b-2)

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Solution for 5=4+2(3b-2) equation: 



5=4+2(3b-2)

We move all terms to the left:

5-(4+2(3b-2))=0



We calculate terms in parentheses: -(4+2(3b-2)), so:

4+2(3b-2)

determiningTheFunctionDomain
2(3b-2)+4

We multiply parentheses

6b-4+4

We add all the numbers together, and all the variables

6b

Back to the equation:

-(6b)



We move all terms containing b to the left, all other terms to the right

-6b=-5

b=-5/-6

b=5/6

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