5=4/5(1)+b

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Solution for 5=4/5(1)+b equation:



5=4/5(1)+b
We move all terms to the left:
5-(4/5(1)+b)=0
Domain of the equation: 51+b)!=0
We move all terms containing b to the left, all other terms to the right
b)!=-51
b!=-51/1
b!=-51
b∈R
We add all the numbers together, and all the variables
-(+b+4/51)+5=0
We get rid of parentheses
-b+5-4/51=0
We multiply all the terms by the denominator
-b*51-4+5*51=0
We add all the numbers together, and all the variables
-b*51+251=0
Wy multiply elements
-51b+251=0
We move all terms containing b to the left, all other terms to the right
-51b=-251
b=-251/-51
b=4+47/51

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