5=4/7(21+3x)=41

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Solution for 5=4/7(21+3x)=41 equation: 



5=4/7(21+3x)=41

We move all terms to the left:

5-(4/7(21+3x))=0



Domain of the equation: 7(21+3x))!=0

x∈R



We add all the numbers together, and all the variables

-(4/7(3x+21))+5=0

We multiply all the terms by the denominator


-(4+5*7(3x+21))=0



We calculate terms in parentheses: -(4+5*7(3x+21)), so:

4+5*7(3x+21)

determiningTheFunctionDomain
5*7(3x+21)+4

Wy multiply elements

35x(3+4

Back to the equation:

-(35x(3+4)



We add all the numbers together, and all the variables

-(35x7=0

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