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5=5(x2-x1)
We move all terms to the left:
5-(5(x2-x1))=0
We add all the numbers together, and all the variables
-(5(+x^2-1x))+5=0
We calculate terms in parentheses: -(5(+x^2-1x)), so:We get rid of parentheses
5(+x^2-1x)
We multiply parentheses
5x^2-5x
Back to the equation:
-(5x^2-5x)
-5x^2+5x+5=0
a = -5; b = 5; c = +5;
Δ = b2-4ac
Δ = 52-4·(-5)·5
Δ = 125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{125}=\sqrt{25*5}=\sqrt{25}*\sqrt{5}=5\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{5}}{2*-5}=\frac{-5-5\sqrt{5}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{5}}{2*-5}=\frac{-5+5\sqrt{5}}{-10} $
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