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5=5-3(v-5)
We move all terms to the left:
5-(5-3(v-5))=0
We calculate terms in parentheses: -(5-3(v-5)), so:We get rid of parentheses
5-3(v-5)
determiningTheFunctionDomain -3(v-5)+5
We multiply parentheses
-3v+15+5
We add all the numbers together, and all the variables
-3v+20
Back to the equation:
-(-3v+20)
3v-20+5=0
We add all the numbers together, and all the variables
3v-15=0
We move all terms containing v to the left, all other terms to the right
3v=15
v=15/3
v=5
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