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5=5/12h
We move all terms to the left:
5-(5/12h)=0
Domain of the equation: 12h)!=0We add all the numbers together, and all the variables
h!=0/1
h!=0
h∈R
-(+5/12h)+5=0
We get rid of parentheses
-5/12h+5=0
We multiply all the terms by the denominator
5*12h-5=0
Wy multiply elements
60h-5=0
We move all terms containing h to the left, all other terms to the right
60h=5
h=5/60
h=1/12
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