5=5/9(y-32)

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Solution for 5=5/9(y-32) equation:



5=5/9(y-32)
We move all terms to the left:
5-(5/9(y-32))=0
Domain of the equation: 9(y-32))!=0
y∈R
We multiply all the terms by the denominator
-(5+5*9(y-32))=0
We calculate terms in parentheses: -(5+5*9(y-32)), so:
5+5*9(y-32)
determiningTheFunctionDomain 5*9(y-32)+5
Wy multiply elements
45y(y+5
Back to the equation:
-(45y(y+5)
We calculate terms in parentheses: -(45y(y+5), so:
45y(y+5
We calculate terms in parentheses: -(45y(y+5), so:
45y(y+5
We calculate terms in parentheses: -(45y(y+5), so:
45y(y+5
We calculate terms in parentheses: -(45y(y+5), so:
45y(y+5
We calculate terms in parentheses: -(45y(y+5), so:
45y(y+5
We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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We calculate terms in parentheses: -(45y(y+5), so:
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